EEman, your first sentence accurately describes my Russound DPA-6.12 amp wiring diagram. But, your second sentence does not seem to follow what I wrote in the text you quoted from me. I am using 4 amp channels, bridged down to two amp channels and arbitrarily designating one of the bridged channels left and one of the bridged channels right, and each separate amp channel has its own positive and negative wire connections (as if I was going to use two separate speakers each one connected to its own bridged amp channel. But in this case I am just using both bridged channels to hook up to two different voice coils of one physical sub (which I undertand should appear for all intents and purposes of making connections as if I were connecting up two separate speakers). In any event, the designated L amp channel positive and negative connections (which in the bridged mono configuration are the L+ and R+, respectively) are connected to the first sub's coil positive and negative; and the R channel postive and negative connections (again, at the amp they are the L+ and R+, respectively) are connected to the second sub's coil positive connection: Therefore L channel's L+ is connected to the first coil's positive, and the L channel's R+ is connected to the first coil's negative; and similarly the R channel's L+ is connected to the second coil's positive, and the R channel's R+ is connected to the second coil's negative. Therefore, unless I am missing something, I believe I hooked it up correctly, both in terms of the manual's wiring diagram and your suggestions of how it should be hooked up with no crossing of negatives and positives. What I do note, however, is that you also suggest (or intimate) that the sub should be hooked to the amp with only one channel and one set of positive and negative speaker wires not two channels and two sets of positive and negative speaker wires. If I did that, I would have the two positives from the sub and one amp positive connected and two negatives from the sub and one amp negative connected; and with that I would effectively loose a channel and the associated power. With all this explanation, do you still think I set it up wrong? If so, I guess I am still missing something.

Ed.